12b^2+17b-7=0

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Solution for 12b^2+17b-7=0 equation:


Simplifying
12b2 + 17b + -7 = 0

Reorder the terms:
-7 + 17b + 12b2 = 0

Solving
-7 + 17b + 12b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-7 + -4b)(1 + -3b) = 0

Subproblem 1

Set the factor '(-7 + -4b)' equal to zero and attempt to solve: Simplifying -7 + -4b = 0 Solving -7 + -4b = 0 Move all terms containing b to the left, all other terms to the right. Add '7' to each side of the equation. -7 + 7 + -4b = 0 + 7 Combine like terms: -7 + 7 = 0 0 + -4b = 0 + 7 -4b = 0 + 7 Combine like terms: 0 + 7 = 7 -4b = 7 Divide each side by '-4'. b = -1.75 Simplifying b = -1.75

Subproblem 2

Set the factor '(1 + -3b)' equal to zero and attempt to solve: Simplifying 1 + -3b = 0 Solving 1 + -3b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -3b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -3b = 0 + -1 -3b = 0 + -1 Combine like terms: 0 + -1 = -1 -3b = -1 Divide each side by '-3'. b = 0.3333333333 Simplifying b = 0.3333333333

Solution

b = {-1.75, 0.3333333333}

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